• Welcome to AppraisersForum.com, the premier online  community for the discussion of real estate appraisal. Register a free account to be able to post and unlock additional forums and features.

Practice exam question

ItDepends

Freshman Member
Joined
Dec 2, 2022
Professional Status
Appraiser Trainee
State
Massachusetts
1.jpg

The answer key says it's D, $12.00/SF. This is the route they take to arrive there:

1. $840,000/35,000SF=$24.00/SF
2. 42,000*0.5=21,000 SF
$514,500/21,000SF= $24.50/SF
3. $60,000 x 0.75=45,000 SF
$1,089,000/45,000 SF= $24.20/SF
4. $2,035,750/85,000SF=$23.95/SF
Mean = $24.16

72,000 SF x 0.5 = 36,000/SF
36,000 SF x $24.16 = $869,850
869,850 SF/72,000 SF = $12.08

I answered A, $12.25/SF. This was my route:

1. $840,000/35,000 SF = $24.00 (FAR 1.0)
2. $514,500/42,000 SF = $12.25 (FAR 0.5)
3. $1,089,000/60,000 SF = $18.15 (FAR 0.75)
4. $2,035,750/85,000 SF = $23.95 (FAR 1.0)

My logic was that land with a greater legally permissible FAR might sell for more per unit because of the greater development potential, and the resulting $/SF data appears to clearly indicate that is true. Since the subject in the question has a FAR of 0.5, I concluded it was more reasonable to use the comp with a FAR of 0.5 exclusively rather than average them all out.

Where am I going wrong here?
 
Sale No. 1 has the FAR most similar to the subject (0.5) and is about an acre, and indicates $12.25 (514,000/4200). The answer closest to $12.25 is "A".
 
The answer is A) $12.25 per square foot of site area.
The trick is recognizing that FAR is the relevant comparison characteristic, so first convert each sale to a price per square foot of allowable building area.
SalePriceSite SFFARAllowable Building SF$/Allowable SF
1$840,00035,0001.0035,000$24.00
2$514,50042,000.5021,000$24.50
3$1,089,00060,000.7545,000$24.20
4$2,035,75085,0001.0085,000$23.95
They cluster extraordinarily tightly around $24 per square foot of allowable building area.
The subject has a 0.50 FAR, so:
$24.50×0.50=$12.25/sf of site area\$24.50 \times 0.50 = \$12.25/\text{sf of site area}
Alternatively, Sale 2 is the most directly comparable because it has exactly the same 0.50 FAR:
$514,500÷42,000=$12.25/sf of land\$514,500 \div 42,000 = \$12.25/\text{sf of land}
Applied to the 72,000-sf subject:
72,000×$12.25=$882,00072,000 \times \$12.25=\boxed{\$882,000}
So the indicated unit value is A) $12.25/sf, implying a site value of $882,000.
This is a good appraisal-exam question because simply calculating the sales' raw $/land-sf figures produces wildly different numbers until you recognize that the differences are almost entirely explained by development density/FAR.
 
The answer is A) $12.25 per square foot of site area.
The trick is recognizing that FAR is the relevant comparison characteristic, so first convert each sale to a price per square foot of allowable building area.
SalePriceSite SFFARAllowable Building SF$/Allowable SF
1$840,00035,0001.0035,000$24.00
2$514,50042,000.5021,000$24.50
3$1,089,00060,000.7545,000$24.20
4$2,035,75085,0001.0085,000$23.95
They cluster extraordinarily tightly around $24 per square foot of allowable building area.
The subject has a 0.50 FAR, so:
$24.50×0.50=$12.25/sf of site area\$24.50 \times 0.50 = \$12.25/\text{sf of site area}
Alternatively, Sale 2 is the most directly comparable because it has exactly the same 0.50 FAR:
$514,500÷42,000=$12.25/sf of land\$514,500 \div 42,000 = \$12.25/\text{sf of land}
Applied to the 72,000-sf subject:
72,000×$12.25=$882,00072,000 \times \$12.25=\boxed{\$882,000}
So the indicated unit value is A) $12.25/sf, implying a site value of $882,000.
This is a good appraisal-exam question because simply calculating the sales' raw $/land-sf figures produces wildly different numbers until you recognize that the differences are almost entirely explained by development density/FAR.
I agree, FAR is the key. My confusion is that the answer key says it's D, $12.00/SF.

EDIT: Sorry if I'm wrong, but is this a bot response? "72,000×$12.25=$882,00072,000 \times \$12.25=\boxed{\$882,000}" restates the same equation, just in LaTex code the second time for some reason. Again here "$24.50×0.50=$12.25/sf of site area\$24.50 \times 0.50 = \$12.25/\text{sf of site area}".
 
Last edited:
Sale No. 1 has the FAR most similar to the subject (0.5) and is about an acre, and indicates $12.25 (514,000/4200). The answer closest to $12.25 is "A".
So it's likely the answer key is incorrect for this question?
 
Find a Real Estate Appraiser - Enter Zip Code

Copyright © 2000-, AppraisersForum.com, All Rights Reserved
AppraisersForum.com is proudly hosted by the folks at
AppraiserSites.com
Back
Top